Do the diagonals of a square (quadrilateral on graph) bisect each other?

Question

For geometry, I plotted points, and it forms a square (I checked with distance formula and slope, it is a square). What does it mean that the diagonals bisect each other?
No lines/rays/segments of the square are dividing another into two equal parts, I don't understand.

Answer 1

The diagonals (you can draw them) bisect each other if the midpoint of one of them is the midpoint of the other. Plot a general square with corners at (0,0), (2a,0), (2a,2a), and (0,2a). Midpoint of diagonal with endpoints (0,0) and (2a,2a) is (a,a). Midpoint of diagonal with endpoints (0,2a) and (2a,0) is also (a,a).

In similar fashion you could prove diagonals of any parallelogram bisect each other.

Answer 2

1 sometimes because quadrilateral could also be a trapezoid 2. never, rhombus sides are all the same and kites are not 3 sometimes, the rectangle could be longer than it is high 4 always, squares have 4 right angles 5. always, squares have 2 pairs of parallel sides 6 always, squares have 4 congruent sides do the others like that

Answer 3

yes they do because the diagnal 1 bisects diagnal 2 and vice versa
see for urself

Answer 4

in a rhombus, diagonals bisect each other. a square is also a rhombus.