find cos θ by using pythagorean identity, sin^2 θ + cos^2 θ = 1
sin θ = 7/8
2007-09-24 16:33:12 · 4 answers · asked by Anonymous in Education & Reference ➔ Homework Help
You open your book and figure it out on your own. he he he he
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2007-09-25 01:57:41 · answer #1 · answered by Angel of Death says F-IT! 6 · 0⤊ 1⤋
if sin Î = 7/8, then
sin^2 Î = 49/64
and if sin^2 Î + cos^2 Î = 1, then
49/64 + cos^2 Î = 1
cos^2 Î = 1 - 49/64 = 15/64
so if cos^2 Î = 15/64 then
cos Î = â15 /8
2007-09-24 23:49:57 · answer #2 · answered by Computer Guy 7 · 0⤊ 0⤋
(7/8)^2 + cos^2 q = 1
49/64 + cos^2 q = 1
cos^2 q = 15/64
cos q = +/- sqrt(15)/8
2007-09-24 23:36:19 · answer #3 · answered by Anonymous · 1⤊ 0⤋
(sinθ)^2 +(cosθ )^2 = 1 ===> (cosθ )^2 = 1-(sinθ)^2
Since, sin θ = 7/8
===> (cosθ )^2 = 1-(49/64) = 15/64
===> cosθ = sqrt (cosθ)^2 = sqrt(15)/8
Hope i am right :)
2007-09-24 23:49:27 · answer #4 · answered by black_tiger 1 · 0⤊ 0⤋