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A Block 6N is pulled along the hypotenuse. What is the work done against friction in pulling the block from bottom of hypotenuse to its top?

2007-09-24 13:14:22 · 1 answers · asked by Ase 2 in Science & Mathematics Mathematics

1 answers

If the block weighs 6N, the potential energy required to lift it is 6×0.04 = 0.24J. However, on the information given, we can't tell how much additional energy is required to overcome friction. On the other hand, if you're saying the block is being pulled with a constant force of 6N, the work done is given by W = Fd = 6×0.05 = 0.3J.

2007-09-24 19:34:09 · answer #1 · answered by Scarlet Manuka 7 · 0 0

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