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Consider any eleven integer numbers, not necessarily distinct. Prove that one can always choose six of these integers whose sum is divisible by five.

2007-09-24 12:19:26 · 2 answers · asked by mshb30 2 in Science & Mathematics Mathematics

2 answers

But is this true? Suppose that the 11 numbers
are all 1. Then any 6 of them add up to 6, which
is not divisible by 5.

2007-09-24 15:36:36 · answer #1 · answered by steiner1745 7 · 0 0

52845785496

5+6+4+8+2+5=30 30/5=6
7+8+5+9+6+5=40 40/5=8

2007-09-24 19:31:59 · answer #2 · answered by charmed 2 · 0 0

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