English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

The 75.8 kg pilot does not want his radial acceleration to exceed 10.3 grams.

a) What is the minimum radies of the circular path?

b) At this radius, what is the net centripetal force exerted on the pilot by the seat belts, the fricion between him and the seat, and so forth?

2007-09-24 11:29:56 · 1 answers · asked by alex v 1 in Science & Mathematics Physics

1 answers

The centripetal force is
m*v^2/r
Is the acceleration in m/s^2? (slightly over 1 g?)
since m=75.8
and v=137 m/s, set up
137^2/r=10.3 m/s^2
and solve for r
1.82 km

The force is 75.8*10.3
or 780 N

j

2007-09-24 11:40:45 · answer #1 · answered by odu83 7 · 0 0

fedest.com, questions and answers