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Express the area A of an isoceles right triangle as a function of the length x of one of the two equal sides.

2007-09-24 10:58:47 · 5 answers · asked by journey 1 in Science & Mathematics Mathematics

5 answers

Area of triangle = 1/2 base * height

With an isosceles right triangle, the base and height are the same since an isosceles triangle has 2 equal sides.

If you call the length of one of the equal sides x, then the area of the triangle is 1/2 (x * x) = 1/2 x^2

2007-09-24 11:15:58 · answer #1 · answered by Jesse 2 · 0 0

A= x^2/2

2007-09-24 11:05:32 · answer #2 · answered by ironduke8159 7 · 0 0

An isosceles triangle is any triangle with 2 factors that are equivalent in length. So each equilateral triangle is a undeniable case of an isosceles triangle in view that not in basic terms 2 factors are equivalent, yet all 3 are. yet each isosceles triangle isn't equilateral, in view which you may have 2 factors of equivalent length and a third area it quite is the two longer or shorter than those 2 factors. as an occasion, if the triangle is a suited-attitude triangle and the two factors that meet to make the suited attitude are the comparable length, then the third area may well be longer than those 2. desire that enables.

2016-11-06 06:52:19 · answer #3 · answered by ? 4 · 0 0

An Isoceles right triangle has 2 equal legs. Therefore, h = x, as does b

So, really, it's A = (1/2)x^2 (since A of a triangle is A = (1/2)bh)

2007-09-24 11:05:25 · answer #4 · answered by zelljrc 2 · 2 0

What's a function? I know the area A of the triangle is (x^2)/2

2007-09-24 11:03:02 · answer #5 · answered by Anonymous · 0 0

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