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My piece of Aluminum foil has a mass of .19 g
Is this a conversion problem? I keep setting it up with Avogadro's Number, but it seems wrong to me.

2007-09-24 09:28:43 · 1 answers · asked by Ariana f 1 in Science & Mathematics Mathematics

1 answers

You have to divide that by the atomic mass of aluminum (which yu fan get off of the periodic chart) That gives you the number of gram-equivalents of aluminum. This is also known as 'moles'. Now multiply that by Avogadros number to get the number of atoms.

Doug

2007-09-24 09:36:22 · answer #1 · answered by doug_donaghue 7 · 0 0

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