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Henrietta is going off to her physics class, jugging down the sidewalk at a speed of 2.95 m/s. Her husbane Bruce suddenly realized that she left in such a hurry that she forgot her lunch of bagels, so he runs to the window of their apt, which is a ht of 45.1 m above the st level and directly above the sidewalk, to throw them to her. Bruce throws them horizontally at a time 4 a after Henrietta has passed below the window, and she catches them on the run. Ignore air resistance.

2007-09-24 08:28:12 · 1 answers · asked by dymestatus 1 in Science & Mathematics Physics

1 answers

When she catches them the following equations must be satisfied

(assuming she catches them at ground level)

0=45.1-.5*g*(t-4)^2
2.95*t=v0*(t-4)
solve for v0
t-4=sqrt(45.1*2/9.81)
t-4=3.03
t=7.03

v0=2.95*7.03/3.03
=6.84 m/s

j

2007-09-26 07:29:38 · answer #1 · answered by odu83 7 · 1 0

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