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molar mass of Na2SO4= 142g/mol
proportion by mass of sodium=46/142*100= 32.4%
of sulphur= 22.5%
of oxygen= 47.1%

2007-09-24 07:47:49 · answer #1 · answered by 8 ball 4 · 0 0

(2 x 23)/142 x 100% for Na, because there are two of them, and 142 is the Mr of the compound and 23 is the Ar for Na.

Similarly, (1 x 32)142 x 100% for S and (4 x 16)/142 x 100% for O.

2007-09-24 14:46:09 · answer #2 · answered by Gervald F 7 · 0 0

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