The tension in a string from which a 4.3kg object is suspended in an elevator is equal to 45N.?

Question

accel of gravity is 9.8m/s^2

what is the magnitufe of the acceleration of the elevator?

What is its direction?

Answer 1

Up at 0.665 m/s

Since the acceleration of the elevator upward is
a
the force acting on an object is
m*(g+a)
since g=9.8 and m=4.3
45=4.3*(9.8+a)
j

Answer 2

Gravitational force is
Fg = ma = 4.3*9.8=42.14N
Total force is 45N so acceleration of the elevator must be providing the difference of 45-42.14=2.86N Then
a=2.86/4.3=.67 m/s²

Doug

Answer 3

You should be paying attention in class foo!