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suppose you use 1.110g of iron. what is the minimun volume of 1.0M copper sulfate solution that you should add?

2007-09-24 05:30:14 · 2 answers · asked by Komodork 3 in Science & Mathematics ➔ Chemistry

2 answers

The reaction
Fe + CuSO4 --------------> Cu + FeSO4

So one mole of Fe (55.845g) is reacting with 1 mole copper sulfate.

Then 1.110g of iron reacts with (1.11 / 55.845) = 0.01987 moles of copper sulfate

As M = n / V ======> V = n / M

So volume of copper sulfate is 0.01987 L = 19.87 ml

2007-09-24 05:50:35 · answer #1 · answered by ADITYA V 3 · 0⤊ 0⤋

Work out (1000/1.0) x (1.11/55.5) cm3 for your answer!

2007-09-24 12:49:36 · answer #2 · answered by Gervald F 7 · 0⤊ 0⤋