Rocket has dry weight 10,000 lb and contains 40,000 lb of fuel in tanks. After ignition the motor burns fuel at constant rate and provides constant force of thrust.
The rocket is launched in vertical direction and continues to acclerate in vertical direction.
Intial accleration of the rocket as it lifts off the launch platform is 0.5g.
[ignore air resiatance]
2007-09-24 05:20:46 · 2 answers · asked by Alexander 6 in Science & Mathematics ➔ Physics
g1 = g at altitude; m0 = 50000, m1 = 10000
f = (g+a0)*m0 = 1.5g*m0 = (g1+a1)*m1
We don't know the duration of acceleration t, specific impulse or mass rate, so can assume it's independent of those and thus set t=0, altitude = 0 and g1 = g.
then 1.5g*m0 = (g+a1)*m1
a1 = 1.5g*m0/m1 - g = 6.5g
2007-09-26 04:53:11 · answer #1 · answered by kirchwey 7 · 1⤊ 0⤋
When the rocket runs out of fuel I would imagine that there is no thrust and hence no acceleration.
2007-09-24 13:59:53 · answer #2 · answered by Mike W 6 · 0⤊ 0⤋