Vector A has a magnitude of 9.60 units and makes an angle of 49.0° counter-clockwise from the positive x-axis. Vector B has a magnitude of 8.00 units and is directed along the negative x-axis.
(a) Using graphical methods, find the vector sum A + B.
*Magnitude of A + B: units
*Direction of A + B: ° counterclockwise from +x-axis
(b) Using graphical methods, find the vector difference A - B.
*Magnitude of A - B: units
*Direction of A - B: ° counterclockwise from +x-axis
2007-09-24 04:03:36 · 2 answers · asked by Foxychick 1 in Science & Mathematics ➔ Physics
Start drawing ☺
Doug
2007-09-24 04:11:23 · answer #1 · answered by doug_donaghue 7 · 0⤊ 0⤋
What you need to do is get the arc tan of vector b/vector a(arc tan of three/6 or 0.5) this gives you you the degress relative from the x axis... purely undergo in recommendations that for area (a) you have a damaging fee and for area b) you have a good.
2016-10-05 06:50:28 · answer #2 · answered by ? 4 · 0⤊ 0⤋