find the coordinates of the vertex of the graph of the function. tell whether the vertex is a max or a min?

Question

1) y=-7x^2-6x-1

2)y=4x^2+8x-1

how do you do something like this

Answer 1

The vertex of y = ax^2 + bx + c is the point (h,k) where
h = -b / 2a and k is the y-value when x is substituted by h.

The vertex is the max point if a < 0 and it is the min if a > 0.

Answer 2

-14x-6=0 so xv= -3/7 Substitute to find y (its a maximum as the coeficient of x^2 is negative
y=(2x+2)^2-5 so vertex (-2,-5) minimum as (2x+2)^2>=0