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Given that dy/dx= (3x-2)^3 & that y=0 when x=1, calculate the value of y where x=1.5?

2007-09-24 03:07:49 · 1 answers · asked by hottie 1 in Science & Mathematics ➔ Mathematics

1 answers

y= 1/12 (3x-2)^4+C
0=1/12+C so C = -1/12
y=1/12(( 3x-2)^4-1))
y(1.5)=3.1719

2007-09-24 03:33:03 · answer #1 · answered by santmann2002 7 · 0⤊ 0⤋

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