How many hydrogens are removed during the Kreb cycle?

Answer 1

for 1 glucose, you get about 10 hydrogens from the kreb cycle. Because hydrogens are carried by 6 NADH and 2 FADH(2) in the kreb cycle and goes to the electron transport chain, but that's a different story.. anyways, so if you do simple math, 6 hydrogens from the 6 NADH plus the 4 hydrogens from the 2FADH(2) you get 10 hydrogens total that is gain and removed . understand, yes, okay, i knew you would

Answer 2

In terms of how many hydrogens are removed by being part of NADH + H+ or FADH2, then the answer is 10 (including the 2 associated with NADH + H+ coming from the conversion of pyruvate to Acetyl CoA. If you are looking for a net number, then you have to subtract out the addition of hydrogens from water at various points in the cycle. Since water enters at 4 points and exits at one point, this gives a net of:

10 H leaving associated with NADH + H+ and FADH2
-8 H coming in from water
+2 H leaving with water

So, 4 net hydrogens actually leave the Krebs cycle with each turn (these are replaced from pyruvate/Acetyl CoA) entering the cycle).

The diagram on this website may help:

http://www.uic.edu/classes/bios/bios100/summer2003/krebsfull.htm