accleration?

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a skier accelerates with the average acceleration of 6.0m/s*2. near the top of the hill, her speed was 15.0 m/s. calculate the time it took her to change her speed to 16.5m/s near the bottom of the hill.

2007-09-24 02:19:01 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

3 answers

t = (v1 - v2)/a

t = (16.5 - 15)/6

t = 1.5/6

t = 0.25 seconds

2007-09-24 02:24:27 · answer #1 · answered by remowlms 7 · 0⤊ 0⤋

To find the time it took her, divide the deltaSPEED (the change in her speed) and divide by the acceleration. In this case, the change in speed is 1.5 m/s, so this divided by 6m/s^2 means it took her 0.25 seconds.

2007-09-24 02:25:58 · answer #2 · answered by KRugg 2 · 0⤊ 0⤋

v= 6t+15
16.5=6t+15 so t = 1.5/6 = 0.25 s

2007-09-24 03:14:46 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋