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How do you solve the equation: x+(x+1)+(x+2)=9
Please show your work.
all the people I've asked to solve this equation, they were either too dumb or too busy to answer. How lame are they?

2007-09-21 21:55:48 · 14 answers · asked by infamous_l00z3r 2 in Science & Mathematics Mathematics

14 answers

here you go:

x+(x+1)+(x+2)=9
x+x+1+x+2=9
3x+3=9
3x=9-3
3x=6
x=6/3
x=2

2007-09-21 22:07:14 · answer #1 · answered by Anonymous · 0 0

x+(x+1)+(x+2)=9
x + x + 1 + x + 2 = 9
3x + 3 = 9
3x = 9 - 3
3x = 6
x = 6/3 = 2

2007-09-21 22:14:19 · answer #2 · answered by Steve B 1 · 1 0

X=2

X+(X+1)+X+2)=9 equivalent 2+(2+1)+2+2)=9

or

2+3+4=9

2007-09-21 22:08:28 · answer #3 · answered by Thoughtfull 4 · 0 0

Given:
x + (x + 1) + (x + 2) = 9
Step 1. Remove the parenthesis
x + x + 1 + x + 2 = 9
Step 2. Add all literal terms and numerical terms
3x + 3 = 9
Step 3. Transpose numerical term
3x = 9 - 3
Step 4. Perform algebraic addition
3x = 6
Step 5. Divide both terms of the equation by 3
x = 2 (Answer)
Hint.
This is a very fundamental algebraic operation (removing of parenthesis and combining like terms) that you should remember.
Good Luck!

2007-09-21 22:08:35 · answer #4 · answered by Anonymous · 1 0

Remove the Brakets now this looks simple....X+X+1+X+2=9
3X + 3=9 3X=6 X = 2 Answer

2007-09-21 22:14:52 · answer #5 · answered by Adeel 2 · 0 0

x + (x + 1) + (x + 2) = 9
x + x + 1 + x + 2 = 9
3x + 3 = 9
3x = 6
x = 2

2007-09-21 22:04:13 · answer #6 · answered by Cider Sid 1 · 1 0

that will be 3x+3=9
3x=9-3
3x=6
x=2; x+1=3; x+2=4

2007-09-21 22:05:09 · answer #7 · answered by criselda 3 · 0 0

gather like terms

3x + 3 = 9
3x = 6
x = 2

2007-09-21 22:01:42 · answer #8 · answered by Beardo 7 · 0 0

x+(x+1)+(x+2)=9

3x + 3 = 9

3x = 6

x = 2

2007-09-21 22:03:12 · answer #9 · answered by Jocel B. Bartolay 2 · 0 0

x+(x+1)+(x+2)=9
3x+3=9
3x=6
x=2, too easy

2007-09-21 22:11:33 · answer #10 · answered by ptolemy862000 4 · 0 0

x+(x+1)+(x+2)=9
3x+3=9
Div by 3
x+1=3
x=2

2007-09-21 22:01:39 · answer #11 · answered by Anis M 1 · 0 0

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