here you go:
x+(x+1)+(x+2)=9
x+x+1+x+2=9
3x+3=9
3x=9-3
3x=6
x=6/3
x=2
2007-09-21 22:07:14
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answer #1
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answered by Anonymous
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x+(x+1)+(x+2)=9
x + x + 1 + x + 2 = 9
3x + 3 = 9
3x = 9 - 3
3x = 6
x = 6/3 = 2
2007-09-21 22:14:19
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answer #2
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answered by Steve B 1
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X=2
X+(X+1)+X+2)=9 equivalent 2+(2+1)+2+2)=9
or
2+3+4=9
2007-09-21 22:08:28
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answer #3
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answered by Thoughtfull 4
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Given:
x + (x + 1) + (x + 2) = 9
Step 1. Remove the parenthesis
x + x + 1 + x + 2 = 9
Step 2. Add all literal terms and numerical terms
3x + 3 = 9
Step 3. Transpose numerical term
3x = 9 - 3
Step 4. Perform algebraic addition
3x = 6
Step 5. Divide both terms of the equation by 3
x = 2 (Answer)
Hint.
This is a very fundamental algebraic operation (removing of parenthesis and combining like terms) that you should remember.
Good Luck!
2007-09-21 22:08:35
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answer #4
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answered by Anonymous
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Remove the Brakets now this looks simple....X+X+1+X+2=9
3X + 3=9 3X=6 X = 2 Answer
2007-09-21 22:14:52
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answer #5
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answered by Adeel 2
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x + (x + 1) + (x + 2) = 9
x + x + 1 + x + 2 = 9
3x + 3 = 9
3x = 6
x = 2
2007-09-21 22:04:13
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answer #6
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answered by Cider Sid 1
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that will be 3x+3=9
3x=9-3
3x=6
x=2; x+1=3; x+2=4
2007-09-21 22:05:09
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answer #7
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answered by criselda 3
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gather like terms
3x + 3 = 9
3x = 6
x = 2
2007-09-21 22:01:42
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answer #8
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answered by Beardo 7
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x+(x+1)+(x+2)=9
3x + 3 = 9
3x = 6
x = 2
2007-09-21 22:03:12
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answer #9
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answered by Jocel B. Bartolay 2
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x+(x+1)+(x+2)=9
3x+3=9
3x=6
x=2, too easy
2007-09-21 22:11:33
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answer #10
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answered by ptolemy862000 4
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x+(x+1)+(x+2)=9
3x+3=9
Div by 3
x+1=3
x=2
2007-09-21 22:01:39
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answer #11
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answered by Anis M 1
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