factorisation, this one is a killer. =]?

Question

9x(3-2x)=10(9x+4)

expand into two brackets and solve x, (both of them)

thanks on that.
i see what i was missing,
its one of those questions were, once you get it wrong the first time you get stuck in that anoying loop.

Answer 1

9x(3-2x)=10(9x+4)
27x - 18x² = 90x + 40
18x² + 63x + 40 = 0
18x² + 15x + 48x + 40 = 0
3x(6x + 5) + 8(6x + 5) = 0
(3x+8)(6x+5) = 0
x = {-8/3, -5/6}

Answer 2

9x(3-2x)=10(9x+4)
27x - 18x^2 = 90x + 40
18x^2 + 63x + 40 = 0
x = (- 63 ± √(63^2 - 4*18*40))/36
x = (- 63 ± √(3,969 - 2880))/36
x = (- 63 ± √1089)/36
x = (- 63 ± 33)/36
x = (- 63 - 33)/36, (- 63 + 33)/36
x = (- 96/36, - 30/36)
x = (- 8/3, - 5/6)

Answer 3

9x(3-2x)=10(9x+4)
or 27x-18x^2=90x+40

or -63x-18x^2=40
or 18x^2+63x+40=0
or 18x^2+48x+15x+40=0
or 6x(3x+8)+5(3x+8)=0
or (6x+5)(3x+8)=0
or x=-5/6or x=-8/3

Answer 4

27x-18x^2=90x+40
27x-18x^2-90x-40=0
18x^2+63x+40=0
18x^2+15x+48x+40=0
3x(6x+5)+8(6x+5)=0
(6x+5)(3x+8)=0
6x+5=0 3x+8=0
x=(-)5/6 x=(-)8/3

Answer 5

27x-18x^2=90x+40
-18x^2+27x-90x-40=0
18x^2-27x+90x+40=0
18x^2+63x+40=0
(3x+8)(6x+5)=0
x=-8/3; x=-5/6