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lim x -> -9 from the left

f(x) = absolute value ( 9x^2-87x +54)/(6x^2-52x-18)


factoring is difficult ...HELP

It has to be a FRACTION so I can't just use a calculator

2007-09-21 19:23:31 · 1 answers · asked by Anonymous in Science & Mathematics Mathematics

1 answers

f(x) = | ( 9x^2-87x +54)/(6x^2-52x-18) |
f(x) = | ( 3x - 27)(3x - 2)/((x - 9)(6x + 2)) |
f(x) = | 3(3x - 2)/(2(3x + 1) |
lim f(x) = | 3(-27 - 2)/(2(-27 + 1)) | =
x→-9
| 3(29)/(2(26)) | =
87/52

2007-09-21 19:56:07 · answer #1 · answered by Helmut 7 · 1 0

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