If 200 feet are required to stop a car traveling 60 miles oer hour, how many feet are required to stop a car traveling 100 miles per hour? Round to the nearest foot.
2007-09-21 19:23:20 · 5 answers · asked by sgregory0020@verizon.net 1 in Science & Mathematics ➔ Mathematics
v² = u² + 2as
v = 0
u² = -2as
Distance is proportional to the square of the velocity.
200 * (100/60)² = 555.56 feet or 556 feet to the nearest foot.
2007-09-21 19:30:28 · answer #1 · answered by gudspeling 7 · 0⤊ 1⤋
Assuming the brakes hold up equally well at stopping from a speed of 100 miles per hour as they did at stopping from 60 miles per hour, we can figure this out with a percentage scale.
f = feet used per mph in order to stop the car.
200/60 = f
3.3333333 = f
In other words, it takes 3.3333333 feet per mph in order to stop this car. If we apply this to 100 mph we get:
100 X f = 333.33333
333 feet is how far the car will travel when trying to stop from moving 100mph.
2007-09-21 19:38:10 · answer #2 · answered by JD 3 · 0⤊ 1⤋
200 ft/ 60 mph * 100 mph = 333 ft
2007-09-21 19:41:24 · answer #3 · answered by 037 G 6 · 0⤊ 1⤋
200 x 20000
----- : ----- ___ 60x = 20000 ___ x = ------ ___ x = 333.33 feet.
60 100 60
This is a ratio problem.
2007-09-21 19:46:03 · answer #4 · answered by Rudey 1 · 0⤊ 1⤋
177.5
2015-11-15 11:40:50 · answer #5 · answered by Debbie 1 · 0⤊ 0⤋