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What are the significant figures of the volume of a cube in cm. cubed with dimensions 12.6 to 12.6 to 12.6 mm. ?

Well, here is what i know. There are 3 significant figures in one of the dimensional values so you estimate to 3 significant figures. !2.6 mm. = 1.26 cm. ; 1.26^3=2.000376 ; the volume then would be 2.00 cm., leaving the trailing zeros alone.

I don't know if i am right. Someone correct me if i am wrong. My teacher didn't teach me anything about this and she expects me to be a wiz at it at the end of the weekend.

2007-09-21 18:25:31 · 4 answers · asked by Anonymous in Science & Mathematics Chemistry

4 answers

If you're multiplying n unsimilar decimal numbers, the more
"precise" number is contaminated by the less precise numbers, so you throw out the extra decimals past those of the number with the least number of significant figures

When multiplying or dividing numbers, the number of significant figures in the result is the same as the least number of significant figures in any of the multiplied or divided terms

2007-09-21 19:12:21 · answer #1 · answered by Anonymous · 0 0

You're almost right. You got the right answer to the right number of significant figures, but you forgot to cube the units. The answer is 2.00 cm³ or 2.00 cc or 2.00 cubic cm

2007-09-21 18:38:51 · answer #2 · answered by Anonymous · 0 0

The variety of sig figs in the main suitable calculated cost would be comparable to that of the quantity with the fewest variety of sig figs used in the calculation. because of the fact that finding the quantity of a cube is multiplying it by ability of all factors and the fewest variety of sig figs is two.5, your answer might desire to basically incorporate 2 sig figs.

2017-01-02 12:27:39 · answer #3 · answered by ? 4 · 0 0

You got it! Now chant to yourself "Your answer should not be any more precise than the least precise input to an equation". May the force be with you.

2007-09-21 18:31:52 · answer #4 · answered by cattbarf 7 · 0 0

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