Total = 440
No. of tests = 5
Average = 44 / 5 = 88
OPTION D
2007-09-21 19:21:58
·
answer #1
·
answered by Como 7
·
2⤊
0⤋
To find out the average, add her test scores up and then divide it by the number of scores.
1) 87+94+79+86+94=440
2) 440/5=88
So the answer is D. 88
2007-09-22 01:10:50
·
answer #2
·
answered by Hello 2
·
0⤊
0⤋
( 87 + 94 + 79 + 86 + 94 ) / 5
= 440 / 5
= 88 ( D )
2007-09-22 01:39:41
·
answer #3
·
answered by fen91 1
·
0⤊
0⤋
first get the sum of her test scores
87+94+79+86+94 = 440
then the divide it with the number of addends that you used.:
440 / 5 = 88
the answer is d.
=)
average is calculated by adding the numbers together, then dividing the total by the amount of numbers
2007-09-22 01:13:08
·
answer #4
·
answered by mY_sHie32 1
·
0⤊
0⤋
to get the average first
1.) get the sum of the given test scores
87+94+79+86+94 = 440
2.) count the no. of the test scores <5>
3.) divide the sum <440> by the no. of the test scores <5>
then you'll come up with...88
it's the answer
2007-09-22 02:16:51
·
answer #5
·
answered by micah_joyce01 2
·
0⤊
1⤋
vaerage of numbers=(87+94+79+86+94)/5
= 440/5
=88
the answer is---D)88
2007-09-22 01:15:15
·
answer #6
·
answered by piyaa 2
·
0⤊
0⤋
79 + 86 + 87 + 94 = 346
Since there are 4 seperate numbers, divide sum by 4.
346 / 4 = 86.5 rounded to 87.
Answer is 87.
2007-09-22 02:22:38
·
answer #7
·
answered by Rudey 1
·
0⤊
1⤋
87
94
79
86
94
-----
440 440/5=88 D
2007-09-22 01:06:03
·
answer #8
·
answered by Dave aka Spider Monkey 7
·
0⤊
0⤋
when ever you are trying to get an average. you add all the scores up or numbers. then you divide you answer by the number of scores you had. in this case you add.
87
94
79
86
94
-----
add them and you get 440
now divide 440 by 5 sence you have 5 scores. this gives you 88. that is your average. always use this to get an average. very easy.
2007-09-22 01:20:26
·
answer #9
·
answered by Missy H 2
·
0⤊
0⤋
the average is the sum divided by the number of events.
so here its 440/5 which equals 88
2007-09-22 01:00:08
·
answer #10
·
answered by bonu rhesus 2
·
1⤊
0⤋