please explain step by step =)
2007-09-21 15:54:40 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
why is it 2Mg + 2O --> 2MGO
and not 2Mg + O --> Mg?
2007-09-21 16:06:42 · update #1
i meant why is it not Mg + O --> MgO
2007-09-21 16:07:10 · update #2
just to clarify the last point you asked, you can't find oxygen in nature as O, it is always found as O2, so that's how it has to be used in equations
2007-09-21 16:32:39 · answer #1 · answered by ChemistryMom 5 · 0⤊ 0⤋
Step 1. Write eqtn
2 Mg+O2 -> 2MgO
Step 2. Divide 1.5 g by 32, the mol wt of dimer O2. Call result M(O2)
Step 3. From equation M(MgO)= 2M(O2).
Step 4. Find mol wt of MgO, call it MW
Step 5. Your answer = M(MgO) * (MW)
2007-09-21 16:02:55 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
2mg+o2--------->2mgo..............this is the reaction.magnesium molwt is 24.If 32gms of oxygen is reacting 80gms of mgo is formed.so,if 1.5g of o2 is acting nearly 1.8gms of mgo is formed................
u cant get oxygen in the form of o...in the nature so we will be taking o2 into consideration and balance the equation accordingly
2007-09-21 16:10:10 · answer #3 · answered by parameswar k 2 · 0⤊ 0⤋
ill assume that Mg (Mr=24.3) is in excess.
2Mg + O2 =2MgO
no. of moles of oxygen = 1.5/(16.0X2) = 0.04688mol
no. of moles of MgO formed = 0.04688 X 2=0.09375mol
mass of MgO formed = 0.09375 X (24.3+16.0)=3.778g
2007-09-21 16:02:39 · answer #4 · answered by Charlie C 1 · 0⤊ 0⤋
16 g O - 40 g MgO
1.5 g O - 3.75 g MgO
2007-09-21 17:10:47 · answer #5 · answered by sg 1 · 0⤊ 0⤋