An object is observed to fall from a bridge, striking the water below 3.09 s later?

Question

An object is observed to fall from a bridge, striking the water below 3.09 s later.
(a) With what speed did it strike the water?

(b) What was the average speed during the fall?

(c) How high is the bridge?

Answer 1

I'll be nice ...

Given that information about air resistance and altitude, etc. are not mentioned, we can probably assume that they are to be discounted. That being the case, the assumptions are:
1) the object's initial velocity is 0.0 m/s
2) it has no wind resistance, and
3) the bridge is on the surface of the Earth, where G is 9.81 m's^2 (to 3 signficant figures)

Therefore:
a) final velocity = 3.09 s * 9.81 m/s^2
= 30.3 m/s

b) average velocity = 30.3 m/s / 2
= 15.2 m/s

c) initial height = 15.2 m/s * 3.09 s
= 46.8 m

Answer 2

Did you observe it from the begginning of the fall? This 3.09s is from the instant of observation or from the begginning of the fall? was it a free fall or a forced fall (throw)? Air resistance was to be counted or not ? Please don't put the answerers in a dilemma.

Answer 3

Impossible to answer, what shape does the object take? is it a feather, or a lead ball? Did it travel in a straight line? Was any force inposed on the object causing it to fall? If so, what direction, and how much force? etc. etc etc.