= 4 [ x - 2 x + 6 ]
= 4 (- x + 6)
= 24 - 4 x
2007-09-23 21:05:25
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answer #1
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answered by Como 7
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1) Write original problem.
2) Remeber GEMDAS:
g = grouping symbols, e = exponents
md = mulitiplication or division (whichever comes first in the equation)
as = addition and subtraction (whichever comes first in the equation)
Therefore, start with the inward-most brackets by distributing.
3) Combine like terms.
4) Distribute.
5) Final Answer!!
1) 4[x-2(x-3)]
2) 4[x-2x+6]
3) 4[-x+6]
4) -4x+24
5) final answer with given info = -4x + 24
2007-09-21 12:49:51
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answer #2
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answered by Anonymous
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First distribute the -2 to (x-3) to get 4(x-2x+6), then solve for the parenthesis to get 4(-x+6), and finally distribute the four to end up with -4x+24.
2007-09-21 12:53:42
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answer #3
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answered by Anonymous
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4[x - 2(x - 3)]=
First work inside the brackets.
= 4[x - 2x + 6]
= 4[-x + 6]
= -4x + 24
2007-09-21 12:48:47
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answer #4
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answered by Christine P 5
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4[x-2(x-3)] = 4[x-2x+6] = -4x+24
2007-09-21 12:35:48
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answer #5
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answered by sahsjing 7
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4[x-2(x-3)]=4[x-2x-6]=4[-x-6] = -4x -24 = 4x + 24
2007-09-21 12:38:30
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answer #6
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answered by Bob Smith 5
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4(x-2x+6) = 4(-x+6) = -4x+24
2007-09-21 12:36:34
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answer #7
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answered by jenh42002 7
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4[x-2(x-3)]=
4[x-2x- 6]=
4x- 8x- 24=
-4x -24=
+24= +24
-4x= 24
-4x/-4= 24/- 4
x= -6
2007-09-21 12:45:45
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answer #8
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answered by bradpaisley90 3
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4[x-2x+6]
4[-x+6]
4x+24
2007-09-21 12:37:20
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answer #9
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answered by crucita 2
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4[x^2-5x+6]=4x^2-20x+30
cheers
2007-09-21 12:40:54
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answer #10
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answered by Anonymous
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