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Question

1. For the following equation, take any two points on the line and calculate the slope: y = 5x - 2.


....Please let me know if i have any mistakes:

y = 5x -2 ; is equivalent to: y = 5(1) - 2

So, the two points would be (5, -2) and (1, -2)

m(slope) = (y2 - y1) / (x2 - x1) = (-2-(-2) / (1-5) = (-2+2) / (1-5) = (0) / (-4). So would the solution or the slope be (0/-4) ?

Answer 1

Wrong, the slope is 5 from the equation.
We can calculate as follow:

The two points are:
x=0, y = -2
x=1, y = 3
m = 3-(-2) / 1-0 = 5

Answer 2

Fist of all the equation y = 5x-2 cannot have a a slope of zero

1. one of the point you could use is the y - intercept calculated as follows:

The graph intercepts the y axis when x is zero (draw the graph and you will see)

so y = 5(0) - 2
y = -2

So 1st point is (0,-2)

2. For the second point take any y value or x value and put it into equation for line

Ill take x = 1. Now put x=1 into equation for the line

y=5(1) -2 so y = 5-2 = 3

So the 2nd point on line is (1,3)

Now we can get the slope

m = change in y / change in x
= 3 - (- 2) / 1-0
= 5

or you could just substitute one of the points into the equation for the line as follows:

Using point (1,3) and y intercept

y = mx + c .................. standard eq for straight line
3 = m(1) -2
m = 3 + 2 = 5

I presume this question is asking you to prove that the slope is 5 because if you notice the slope is given in the equation you were given:

compare y = mx + c
with y = 5x - 2

Hope that helps.

Answer 3

I think the most useful form of straight-line equations is the "slope-intercept" form:

y = mx + b

This is called the slope-intercept form because "m" is the slope and "b" gives the y-intercept.

So, the slope m is 5, m = 5, and b = -2

If you need to take any 2 points (A,B) on this line, then take for example:
x = 0, then y = 5(0) - 2, that means A(0, -2)
Take the second point, for example, y=0. That means:
0 = 5x - 2 ==> 5x = 2 ==> x = 2/5, B(2/5, 0)

So, your 2 points are: A(0, -2) and B(2/5, 0)

Answer 4

y = 5x -2 is in the slope intercept form so slope =5

But you can set y = 0 which gives x= .4 so (.4,0) is one point on the line. Now set x= 0, so y= -2, so (0,-2) is another point on the line. Slope = difference in y values divided by difference in x values = (-2-0)/(0-.4 = -2/-.4 = 5.

If y=mx+b, then m is the slope and b is the y-intercept.

Answer 5

lol wow, such an odd question

first of all the coefficient for x in any linear equation IS the slope, so when you take two points and calculate slope you had better get 5

when x = 0, then y = -2
when x = 1, then y = 3

slope equals delta y / delta x = (3-(-2)) / (1-0) = 5

Answer 6

You made a mistake:

What are two points on the line?

First we need to pick two random x values:
I pick 0 and 2

Now we plug these x values into the equation to find their partner y values:

y = 5(0) -2
y = -2

y = 5(2) -2
y = 10 - 2
y = 8

So now we have two points on the line:
(0,-2) and (2,8)

Now use your slope formula with these two points and you should find that m = 5. Give it a try!

Note: Your mistake was in how to find points on the line not in computing the slope given two points. You can chose any x values randomly and they should work - Have fun!

Answer 7

"is equivalent to: y = 5(1) - 2

So, the two points would be (5, -2) and (1, -2)"

???

you give values for x, choose simple values
if x=0, then y =5*0-2=-2
if x=1, then y=5*1-2=3

So the points are (0,-2), (1,3)

it seems you know to compute the slope

Answer 8

the slope is 5..to get that just use the points 0, -2