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An airplane flies at airspeed (speed relative to air) 145km/h. THe pilot wishes to fly due West but there is a 29.9 km/h wind blowing in from North to South.
a) In what direction should the pilot head the plane?
b) What would be the ground speed of the plane (its speed relative to the ground)?

Please explain..mas confusion :( Thanks everyone!

2007-09-21 11:51:25 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

Draw the diagram. It's a right triangle with hypotenuse 145 and one leg 29.9.
a) Direction:
arcsin(29.9/145) = 11.9 degrees north of west.
b) Ground speed:
145cos11.9 = 141.88km/h

2007-09-21 23:08:13 · answer #1 · answered by jsardi56 7 · 0 0

The West component of the wind speed = (60)(sin45) = forty two.4 km/h. If the pilot needs to fly due North, the East component of his speed would desire to be the comparable by using fact the West component of the wind speed, consequently (a hundred ninety)(sin theta) =forty two.4 km/h => sin(theta) = 0.2233 => theta = 12.9 ranges

2016-12-17 07:10:11 · answer #2 · answered by ? 4 · 0 0

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