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I really don't know how to do this.....

A quartic function passes throught he points (-2, 45), (-1, 48), (0, 45), (1, 48), and (2,45). Determine the equation of the function that passes through these points.

10 points to the first person who can give me the answer.

2007-09-21 11:41:43 · 4 answers · asked by tmlfan 4 in Science & Mathematics Mathematics

To jenh42002, why do you have to fill in 45 for all the E values? And after that, how did you "get" the values for the coefficients?

2007-09-21 12:34:01 · update #1

4 answers

Ax^4 + Bx^3 + Cx^2 + Dx + E = f(x)


With (-2, 45) we get

16A - 8B + 4C - 2D + E = 45

With (-1, 48) we get

A - B + C - D + E = 48

With (0, 45) we get E = 45

With (1,48) we get A+B+C+D+E = 48

With (2,45) we get 16A + 8B + 4C + 2D + E = 45

Filling in 45 for all the Es, we have

16A - 8B + 4C - 2D = 0 --> 8A-4B+2C-D = 0
A -B+C-D+45= 48 ------> A-B+C-D = 3
A+B+C+D + 45 =48 ----> A+B+C+D = 3
16A+8B+4C+2D = 0 ----> 8A+4B+2C +D = 0

I get A = -1, C= 4, B = 0, D = 0, so

-x^4 + 4x^2 + 45 = f(x)

2007-09-21 12:00:54 · answer #1 · answered by jenh42002 7 · 0 0

y = ax^4+bx^2+45
45 = 16a+4b+45 => 4a+b = 0......(1)
48 = a+b+45 => a+b = 3......(2)
(1)-(2), 3a = -3
a = -1
b = 4
y = -x^4+4x^2+45
-----------
Ideas: The quartic function is an even function.

2007-09-21 11:54:01 · answer #2 · answered by sahsjing 7 · 0 0

P(x) = x^4 - 4x^3 + 3x^2 + 4x - 4 First, locate the 1st by-product or P'(x) 4x^3 - 12x^2 + 6x + 4 (divide the entire term through 2) 2x^3 - 6x^2 + 3x + 2 then do the exchange branch technique 2 - 6 + 3 + 2 l_2_l 4 -4 -2 -------------------- 2 - 2 -one million 0 2x^2 - 2x - one million then use the quadritic formulation the solutions must be 2, -0. 37, and1.37 in case you will use the quadratic formulation you will possibly get an answer with an intensive.

2016-10-19 08:38:58 · answer #3 · answered by ? 4 · 0 0

(x,y) = (+1,+3)

2007-09-21 11:50:52 · answer #4 · answered by Loveleen 2 · 0 2

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