How do you solve this math question?

Question

three consecutive integers are listed in increasing order. if their sum is 102, what is the second integer in the list?

A. 28
B. 29
C. 33
D. 34
E. 35

Answer 1

x + (x + 1) + (x + 2) = 102

3x + 3 = 102

3x + 3 - 3 = 102 - 3

3x = 99

3x/3 = 99/3

x = 33

Thus, 33, 34, and 35 are your three consecutive integers, and the second one is 34.

Answer 2

D!
33+34+35=102!

Answer 3

D = 34.

Because 33 + 34 + 35 = 102.

Answer 4

This is a simple algebra problem. Set it up like this
x + x+1 + x+2 = 102.
Now group so you get this 3x +3 =102.
Then group again.
3x=99
Now solve for x
x=33
therefore the 2nd integer is D. (34)
Let the words tell you how to set up the problem.

Answer 5

let 1st no. = x 2nd no.= x +1 3rd no. = x+2
so when you add them up:
x + (x+1) + (x+2) = 102
combine like terms:
3x + 3 = 102
transpose the constant 3 to the other side of the equation, so that means you subtract it from 102:
3x = 102 - 3 --> 3x = 99
then you divide them by three so that you'll be left with x:
x = 33
x + 1 = 34
x + 2 = 35
the numbers are 33,34 and 35.

Answer 6

Here's how I did it:

102/3 = 34

If you add 33, 34, 35.... you get 102

Answer: 34

Answer 7

34

33+34+35=102

Answer 8

33 + 34 + 35 = 102...so the answer is D.

Answer = D

Answer 9

Let x=a number, x+1=next number, x+2=the third

Equation.............

(x+1) +(x+2)+ (x+3)=102

Combine like terms and solve for x. This is the first integer, follow the first line to get the others.

Good luck!

Answer 10

D. 34