What outcomes are equally likley in the sums of two dice?

Answer 1

2 and 12 both have a prob of 1/36
3 and 11 both have a prob of 1/18
4 and 10 both have a prob of 1/12
5 and 9 both have a prob of 1/9
6 and 8 both have a prob of 5/36
7 has a prob of 6/36 = 1/6

Answer 2

Hi Tiff

Look at it this way. You have 36 possible outcomes as follows:

(1/1);(1/2); (2/1);(2/2);(3/1);(3/2);(1/3);(2/3);(3/3);(4/1);(4/2);(4/3);(1/4);(2/4);(3/4);(4/4);(5/1);(5/2);(5/3);(5/4);(1/5);(2/5);(3/5);(4/5);(5/5);(6/1);(6/2);(6/3);(6/4);(6/5);(1/6);(2/6);(3/6);(4/6);(5/6);(6/6)

Now if you add the total of the dice you will get the following distribution:

2 -1 time
3 - 2 times
4 - 3 times
5 - 4 times
6 - 5 times
7 - 6 times
8 - 5 times
9 - 4 times
10 - 3 times
11 - 2 times
12 - 1 time

which is 36 outcomes. So -- 2-12 each occur 1 time. 3-11 each occur twice. 4-10 each occur 3 times; 5-9 each occur 4 times; 6-8 each occur 5 times; and 7 occurs 6 times.

Hope this helps.

Answer 3

2 and 12
3 and 11
4 and 10
5 and 9
6 and 8

Answer 4

1 and 12 1/36
2 and 11 2/36
3 and 10 3/36
4 and 9 4/36
5 and 8 5/36