2 math problems?*10 points*?

Question

simply simplify.

x to power of 3y to power of 0x to power of -7.

and

(5to power of -2)-2 over
(2r to power of 3)2


thanks in advance, 10 points.

Answer 1

x^3 y^0 x^(-7)
= x^(3 + -7) y^0
= x^(-4) y^0
= x^(-4) * 1
= x^(-4)
= 1 / x^4



Do you mean:
[5^(-2)]^-2 / [2r^3)^2
= 5^(-2 * -2) / {2^2 r^(3*2)}
= 5^4 / (4r^6)
= 625 / 4r^6

Answer 2

x to power of 3y to power of 0x to power of -7= 1, since anything raised to the 0 power is 1.

[(5^-2)^-2]/(2r^3)^2
=625/4r^6

Answer 3

1. If you mean x^(3y^(0x^-7))
then 0x = 0
0^-7 = 0
3y^0 = 3

x^3 is the answer.

It is not clear to me if this is what you mean, or if you mean
x^(3y)^(0x)^-7
in which case (0x)^-7 = 0
(3y)^0 = 1

x is the answer.

I really can't tell where your parentheses should be in the second one.
((5^-2) - 2)/((2r^3)2)
would be ((1/25)-2)/(4r^3)
or (49/25)/(4r^3)
= 49/(100r^3)
but I don't know if the question is written out correctly.

Answer 4

((x^3)^0)^(-7) = 1^(-7) = 1/1^7 = 1.000000

The x drops out because anything to the zero power = 1.

((5^(-2))^2)/((2r)^3)^2
(1/(5)^2)^2/(2r)^5
(1/25)^2/(2r)^5
(1/625)/32r^5
1/20000r^5

anything to a negative power is the recoprical. 2^(-2) = 1/4

Answer 5

first one should be 1 cause anything to the power of 0 is 1

Second one should be worked out like this if i interpreted it correctly
((5^-2)^-2)/(2r^3)^2
= 625/(4r^6)

Answer 6

x ^ 3y ^ 0x ^ -7 = x ^ 3y ^ 0 = x ^ 1 = x

(5^-2 - 2) / ((2r)^3 * 2) = (1/25 - 2) / (16r^3) =
(-49/25) / (16r^3) = -49/(400 r^3)

Answer 7

we in lots of situations write: -4^2, -2^(-3) a million) sixteen damaging situations damaging continuously equals advantageous 2) a million/(-8) while some thing is to the means of a damaging form it skill one over the respond with out the damaging means (exponent) so -2^(-3) = a million/(-2^3)

Answer 8

oops, sorry i dont get math problems like that so far. hehe