lim x-> infinity for 12x+3/3x
how do i do this? i love getting sent home with homework we haven't covered yet
2007-09-21 08:12:08 · 5 answers · asked by alfreddood 1 in Science & Mathematics ➔ Mathematics
ummmmm 4
2007-09-21 08:18:57 · answer #1 · answered by Anonymous · 0⤊ 0⤋
I don't know if you divide the entire equation by 3x or just the three...but if it's 3/3x , then take limit of each part...lim of 12x as x goes to infinity is infinity because if you keep increasing x , 12x is going to increase... now 3/3x goes to 0 because as x goes to infinity the denominator gets bigger, and the bigger the denominator the smaller the value of 3/3x so the limit of that goes to 0....and infinity + 0 = infinity.
2007-09-21 15:36:00 · answer #2 · answered by falconbenz10 1 · 0⤊ 0⤋
supposing (12x+3)/3x= 4+1/x and 1/x==>0 so the lim=4
2007-09-21 15:18:35 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋
(12x+3)/3x
= 12x/3x + 3/3x
= 4 + 1/x
= 4 + 0
= 4
whenever you have 1/x, that goes to zero... because if you divide 1 by a really big number & even a really bigger number, it gets closer & closer to zero.
2007-09-21 15:23:59 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Answer: 4
Either use L'Hopital's Rule or just go with finding the horizontal asymptote.
Finding the horizontal asymtote is one less step, but they pretty much take less than one second (no I'm not joking).
You just look at it and say 12 / 3 which is 4.
Using L'Hopital's rule, you differentiate top and bottom amd find limit
12 / 3 = 4
2007-09-21 15:16:52 · answer #5 · answered by UnknownD 6 · 0⤊ 0⤋