I need help with a graphing problem?

Question

the problem is
a) graph 6-x for x = 1 (the = sign has slash through it)
and -5, for x = 1

b) find lim x-> 1 f(x)

c) find f (1)

d) is f continuous at 1?

how do i do this? I have a ti-83 calculator but am NO good with it,

Answer 1

y <> 6-x {<> means not equal to}
Pretend y = 6-x
Then when x = 0, y =6 so we have the opoint (0,6)
When y= 0, x = 6 so we have the point (6,0).
So draw a dashed line through these two points, extending it as far as you like in both directions.

So any point not on the dashed line is a solution to y<>6-x.

f(x) = 6-x
So f(1) = 5

lim f(x) x --> 1 = 5

f(x) is continuous everywhere

I hope I understood the question. Did you copyit exactly as it was written?