can anyone help me with this, this is just one of many i dont get
2007-09-21 07:55:26 · 5 answers · asked by jake p 2 in Science & Mathematics ➔ Mathematics
f(x + h) = 2 (x + h) ² + 5(x + h)
f(x + h) = 2(x ² + 2 h x + h ²) + 5 x + 5 h
f(x + h) = 2 x ² + 4 h x + 2 h ² + 5 x + 5 h
f(x + h) = 2 x ² + (4 h + 5) x + (2 h ² + 5 h)
2007-09-25 07:45:26 · answer #1 · answered by Como 7 · 0⤊ 0⤋
f(x) = 2x^2 +5x
f(x+h)=2(x+h)^2+5(x+h)
=2(x^2+2xh+h^2)+5x+5h
=2x^2+4xh+2h^2+5x+5h
2007-09-21 08:19:41 · answer #2 · answered by Anonymous · 0⤊ 0⤋
When you have f(...) means that you have to REPLACE the x of the equation with (...) that is mentioned.
Example:
If f(x) = 2.x; then f(a) = 2.a
Therefore, if f(x) = 2.(x)^2 + 5.(x)
then f(x+h) = you get it...
Thanks,
Lou
2007-09-21 08:06:31 · answer #3 · answered by luisfer_reyes 2 · 0⤊ 0⤋
f(x+h)=2(x+h)^2+5(x+h)
=2(x^2+2hx+h^2)+5x+5h
=x(2x+5)+h(2h+5)+4hx
2007-09-21 08:09:53 · answer #4 · answered by barakota 1 · 0⤊ 0⤋
f(x+h)=2(x+h)^2+5(x+h)
=2(x^2+2xh+h^2)+5(x+h)
=2x^2+4xh+2h^2+5x+5h
=2(x^2+h^2)+4xh+5(x+h)
2007-09-21 08:48:02 · answer #5 · answered by Ghanim 2 · 0⤊ 0⤋