let be the number,
= 3<1abcde>
100000a + 10000b + 1000c +100d + 10e +1 = 300000 + 30000a + 3000b + 300c + 30d + 3e
70000a + 7000b + 700c + 70d + 7e = 299990 {rearranging}
10000a + 1000b + 100c + 10d + e = 42857 {divide everything by 7}
= 42857
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alternatively:
let be the number,
10 + 1 = 3(100000 +)
10 + 1 = 300000 + 3
7 = 299999
= 42857
2007-09-21 07:30:34
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answer #1
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answered by NeXtrews 4
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Adding a 1 to the left hand side of a five digit number is like adding 100000 to it, and adding a 1 to the right hand side of a five digit number is like multiplying the number by 10 and then adding 1, so you know:
3 * (100000 + x) = 10x + 1
300000 + 3x = 10x + 1
299999 = 7x
x = 42857
2007-09-21 14:36:57
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answer #2
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answered by Jeremiah F 3
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Let a, b, c, d, and e be the digits in this number.
10,000a + 1,000b + 100c + 10d + e is your number.
100,000a + 10,000b + 1,000c + 100d + 10e + 1 is your number with a 1 to the right of it.
100,000 + 10,000a + 1,000b + 100c + 10d + e is your number with a 1 to the left of it.
(100,000 + 10,000a + 1,000b + 100c + 10d + e) x 3 = 100,000a + 10,000b + 1,000c + 100d + 10e + 1
300,000 + 30,000a + 3,000b + 300c + 30d + 3e = 100,000a + 10,000b + 1,000c + 100d + 10e + 1
299,999 = 70,000a + 7,000b + 700c + 70d + 7e
Divide everything by 7:
42,857 = 10,000a + 1,000b + 100c + 10d + e
There's your answer.
Checking: 428,571 / 142,857 = 3
2007-09-21 14:37:30
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answer #3
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answered by Lucas C 7
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Five digits: a, b, c, d, e.
100000a + 10000b + 1000c + 100d + 10e + 1 = 3*[100000 + 10000a + 1000b + 100c + 10d + e]
2007-09-21 14:28:41
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answer #4
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answered by Mathsorcerer 7
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it can't be
because if it is
say
1xxxxx
and
xxxxx1
number of digits is same
and it is the same number
then 1xxxxx*3 has to be
1xxxx(x has to be equal or more to 3)
ie..the digit inthe units place
has to be 3 or more than 3
and since digits being the same
you can't achieve this task
2007-09-21 14:53:14
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answer #5
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answered by jp_iyer 2
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(10X + 1) = 3*(100000 + X)
10X + 1 = 300000 + 3X
7X = 299999
X = 42857
2007-09-21 14:33:37
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answer #6
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answered by PMP 5
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