I'm having a brain fart. I should REALLY remember how to do this, but I don't:
wz(sqrt 12w) + 2wz(sqrt 3w)
Thank you!
2007-09-21 05:43:00 · 8 answers · asked by chrizzle08 2 in Science & Mathematics ➔ Mathematics
the index and the radicand should have the same value...
wz(sqrt(4)(3)(w)) + 2wz(sqrt 3w)
2wz(sqrt 3w) + 2wz(sqrt 3w)
4wz(sqrt3w)
4wx(sqrt3w)
2007-09-21 05:52:45 · answer #1 · answered by Grand Phuba 5 · 0⤊ 0⤋
Remember that you can only add similar radicals or radical expressions having the same index and the same radicand.
wz(sqrt 12w) + 2wz(sqrt 3w)
The radical expressions have the same index, since they are both square roots. But the radicands are not similar. However, we can simplify the first one so that it will be similar to the second.
wz(sqrt 12w)
Factor 12w into 4(3w). Since 4 is a perfect square, then
wz(sqrt 12w)
= wz (sqrt 4(3w))
= 2wz (sqrt 3w)
So the sum is
wz(sqrt 12w) + 2wz(sqrt 3w)
= 2wz (sqrt 3w) + 2wz(sqrt 3w)
= 4wz (sqrt 3w)
2007-09-21 05:55:39 · answer #2 · answered by tangy 5 · 0⤊ 1⤋
wz(sqrt 12w) + 2wz(sqrt 3w)
=2wz sqrt(3w)+2wzsqrt(3w)
=4wzsqrt(3w)
2007-09-21 05:58:49 · answer #3 · answered by ironduke8159 7 · 1⤊ 0⤋
wz(sqrt 12w) + 2wz(sqrt 3w)
wz(sqrt 4*3w) + 2wz(sqrt 3w)
2wz(sqrt3w) + 2wz(sqrt 3w)
4wz(sqrt 3w)
2007-09-21 05:53:04 · answer #4 · answered by fcas80 7 · 0⤊ 0⤋
wz*sqrt(12w) = wz*sqrt(4*3*w) = 2wz*sqrt(3w)
Add that to 2wz*sqrt(3w) and you get 4wz*sqrt(3w).
2007-09-21 05:52:17 · answer #5 · answered by PMP 5 · 0⤊ 0⤋
w z (2â3) w + 2 w z â3 w
2â3 w ² z + 2â3 w ² z
4â3 w ² z
2007-09-21 23:54:37 · answer #6 · answered by Como 7 · 2⤊ 0⤋
4wz(sqrt(3w)...sqrt(12w)=2sqrt(3w)
2007-09-21 06:00:06 · answer #7 · answered by savager 1 · 0⤊ 1⤋
wzsqrt+12wzw+2wzsqrt+6wzw=3wzsqrt+18wzw
2007-09-21 05:52:20 · answer #8 · answered by vhentesiete 1 · 0⤊ 0⤋