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the second of two numbers is 4 more than the first. The sum of the numbers is 56.
If x represents the first number, and y represents the second number, what are the numbers?

If you answer, can you show me HOW you got your answer?

2007-09-21 04:38:13 · 3 answers · asked by emzahlee 2 in Science & Mathematics Mathematics

3 answers

Let x by the smaller number. Then y is the larger number and the problem tells you that
y = x + 4
and also that
x + y = 56.
Make the substitution for y and get
x + x + 4 = 56
2x + 4 = 56
2x = 52
x = 26 and y=x+4 = 30
check
26 + 30 = 56 so we're kewl.

Doug

2007-09-21 04:47:57 · answer #1 · answered by doug_donaghue 7 · 0 0

y = 4 + x {the second of two numbers is 4 more than the first}
x + y = 56 {The sum of the numbers is 56.}

substitute first eqn to second eqn
x + x + 4 = 56
2x = 52
x = 26

substituting x to first eqn
y = 4 + 26
y = 30

the two numbers are (x =) 26 and (y =) 30.

2007-09-21 11:52:36 · answer #2 · answered by NeXtrews 4 · 0 0

X + Y = 56
Y = (4 + X) Four more than the first
X + 4 + X = 56 Now collect like terms
2X + 4 (-4)= 56 (-4)
2X = 52
X = 26
So the numbers are
X = 26
Y = 4 + 26 = 30

2007-09-21 11:47:42 · answer #3 · answered by a_talis_man 5 · 0 0

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