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A baseball is thrown with a velocity of 16.4 m/s at an angle of 30 degrees to the horizontal. Determine the horizontal displacement of the baseball.

Please show all the steps
Thanks!

2007-09-21 01:29:19 · 7 answers · asked by Sandra 2 in Science & Mathematics Physics

7 answers

The movement of the baseball has two components, the horizontal and the vertical. For this question, we assume that the ground is level.

To calculate the horizontal distance travelled, you need to know its horizontal velocity, and the time of flight. The horizontal velocity is 16.4 cos30 m/sec.

The vertical component of the velocity is 16.4 sin 30, so you now calculate the time that it would take a body shot vertically upwards with a velocity of 16.4 sin30 m/sec to return to the ground, and don`t forget that you must consider the upward and downward movements.

You now use distance travelled = average speed x time taken
to find the horizontal distance.

Hope this helps, Twiggy.

2007-09-21 02:44:46 · answer #1 · answered by Twiggy 7 · 1 1

Angle 30 Degrees Sin 30 = 0.5

Horizontal velocity = 0.5* 16.4
Vertical Velocity = 16.4 - Horiz vel.
Time of flight is time to reach max hight and return to ground

Hor displacement = 8.2*t

2007-09-21 10:02:15 · answer #2 · answered by Anonymous · 1 0

You have not been paying attention in class.

horizontal velocity = 16.4 * cos 30°

If you want to calculate displacement, you must specify a time period.

2007-09-21 08:37:08 · answer #3 · answered by Computer Guy 7 · 0 2

horizontal displacement in the air?


simply divide the vectors, (x and y)

calculate the gravitational pull in the x direction to find the t.o.f. use that number to solve the y component and you're there...

2007-09-21 08:36:27 · answer #4 · answered by Anonymous · 0 0

ive not got a calculator on me, but if i were you, id measure the horiozontal component of the velocity through 16.4 x cos 30.

2007-09-21 08:46:49 · answer #5 · answered by Anonymous · 0 3

There's a simple equation for that, girl...

I won't tell you what it is, because that defeats the purpose of learning...the whole point of learning is not to just memorize an equation and the applications that equation can be used for...

...but to learn how to "figure out" where to find information...(so figure out where you would find the equation, find it, and then use it...and obtain the answer...the steps will reveal themselves once you get the equation...and memorize that puppy forever...)

Those are the "steps" you need to go through to "really" get the answer to your question right...(my answer to your question is the "true" help that you need with this problem)

2007-09-21 08:40:03 · answer #6 · answered by Anonymous · 0 2

ahhhhhh does were the days.
Ur on ur own. lol.

2007-09-21 08:34:13 · answer #7 · answered by Qwerty 2 · 0 2

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