could you help me solve this maths problem lowest comman multiple of 24 30 and54 is there a formulae?

Question

i have just started redoing my gcse

Answer 1

First, write each integer as a product of its prime factors, but use the same primes for all three, even if some primes occur to the zero power:

24 = (2^3)*(3^1)*(5^0)
30 = (2^1)*(3^1)*(5^1)
54 = (2^1)*(3^3)*(5^0).

Now the LCM is found by taking these same primes, each raised to the highest power which occurs in the above array:

LCM = (2^3)*(3^3)*(5^1) =1080.

Answer 2

Ah divide everything by 6

24/6 = 4
30/6 = 5
54/6 = 9

Then 4 x 5 x 9 x 6 = 1080

Answer 3

Divide by the highest common denominator and multiply those answers by eachother and then the common denominator

24/6=4
30/6=5
54/6=9

9*5*4*6=1080

Its easier to find the highest common denominator in this case. I dont know of any formula. sorry

Answer 4

lowest common multiple is 2

Answer 5

If you use the "tree" method - you can never go wrong.

24
|--------|
8 3
2,2,2,3

30
|--------|
6 5
3,2,5


54
|--------|
6 9
3,2 3,3

Now you need to select all that exist and are not common:

3,3,3,2,2,2,5

540
So 3x3x3x2x2x2x5 = 1080

Hope this helps.