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6 answers

I'm not sure what the "opposite" side would be on the triangle since it only has three sides by definition. Furthermore, since the hypotenuse=1 (given), both the remaining sides must be less than one.

2007-09-20 17:43:20 · answer #1 · answered by Lee W. 5 · 1 0

The hypotenuse is the longest side of the triangle, hence no side can be longer than one!

Draw the 30-60-90 triangle, the side opposite 90 is the hypotenuse, call it one.

The thing to remember is the side opposite 30 = 1/2.

Once you know this, then you can figure out that the side opposite 60 = sqrt (1 - (1/2)^2) , Pythagorean Thm.

= sqrt(1 - 1/4)

= sqrt (3/4)

= sqrt(3) / 2.

Check the values of sin (30) and sin(60) and you will see the above is right.

2007-09-20 17:40:38 · answer #2 · answered by pbb1001 5 · 0 0

Actually, I think the triangle you're looking for has opposite side 1 and hypotenuse 2.

Draw out your triangle with the 30° angle in the lower left and the 90° angle in the lower right. We know that sin(30) = Opp/Hyp, and if we multiply both sides of this equation by Hyp we get:

Hyp*sin(30) = Opp

So taking Hyp to be 2 (instead of 1), we get:

2*sin(30) = 1 = Opp. So we know 1 = the Opposite side.

2007-09-20 17:41:06 · answer #3 · answered by jlukew 2 · 0 0

If you are finding the hypotenuse of a right triangle - here is the equation - a^2 + b^2 = c^2

2007-09-20 17:42:01 · answer #4 · answered by palerider_2006 3 · 0 0

You got it backwards. If the hypotenuse is 2, the smallest side is 1. The sine of 30 deg is 1/2.

2007-09-20 17:39:43 · answer #5 · answered by cattbarf 7 · 0 0

No side of a triangle can be bigger than the hypotenuse. If you know hypotenuse is equal to one, then all the others have to be less than 1.

2007-09-20 17:38:10 · answer #6 · answered by Zack Wilder 3 · 1 0

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