Algebra help?

Question

The direction says "Find the equation of the line described in slope-intercept form" The question is: Has an x-intercept of 5 and a y-intercept of -3. I know where the -3 belongs but I don't know where to plug in the -5. Please explain :]
Thanks

Answer 1

m = [ 0 - ( - 3 ) ] / (5 - 0) = 3 / 5
Line passes thro` (5 , 0)
y - 0 = (3/5) (x - 5)
y = (3/5) x - 3

Answer 2

An intercept means the point where the line cuts the x- or y-axis.

In an intercept form, the equation of ur line would be

x/5 + y/(-3) = 1

you now simplify the above equation to get it to "y=m*x+c" form

multiply eq. by 15, u get

3x -5y=15;
or, 5y=3x-15
or, y=(3/5)x - 3

so, the slope is 3/5, and y-intercept is -3.

Answer 3

Y = mX + b

From the question, we know that our b value is - 3 so all we have to find now is the slope m.

Formula for calculating slope is:

(y1 - y2) / (x1 - x2)

An x-intercept of 5 = (5, 0)
A y-intercept of - 3 = (0, -3)

Now you can plug the points into the formula:

m = (0 - -3) / (5 - 0)
m = 3/5

Therefore,

Y = 3/5x - 3

Answer 4

Use defniition of slope. rise over run. Between the two points given, it rises -3, and runs 5, so the slope is -3/5. You know the y-intercept, so plug it in:

y=(-3/5)x -3

Answer 5

slope intercept form means

y = mx + b, where m is the slope, b is the y-intercept.

This is the form of the equation you want.

You are given two points, (5,0) and (0,-3).

First, figure out the slop of the line.

(0 - -3)/(5 - 0) = 3/5 = m.

The y-intercept = -3, that's b, so the line is

y = (3/5)x -3.

Done.

Answer 6

Hello,

We have y = mx -3 so for the x-intercept we let y = 0 and x = 5 giving us 0 = m(5) -3 so m = 3/5 so we have y = 3/5x - 3

Hope This Helps!!