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2007-09-20 16:32:23 · 13 answers · asked by LADY V, 1 in Science & Mathematics Mathematics

13 answers

(4x - 3) (2x + 5) = 0
x = 3 / 4 , x = - 5 / 2

2007-09-23 21:22:24 · answer #1 · answered by Como 7 · 0 1

OK - lets see how we can show this for you

8x^2 +14x -15 =0. These can be tricky since you have several factors. Trying factors you can quickly get to the right ones which are (4x-3) and (2x+5). Note that you know the two signs have to be different since the ending item (15) is negative. Also, you know that the x are going to be either 8 and 1 or 4 and 2. It takes a little practice but once you get this part, the rest is easy.

Now lets complete the work:

(4x-3)(2x+5) =0 solving for x. Since either factor can be 0 we need to find 2 solutions, 4x-3=0 and 2x+5=0

4x-3=0
4x=3
x=3/4 is one answer.

2x+5=0
2x=-5
x=-5/2 is the other answer.

So your answers are x=3/4 and x=-5/2. Now check your work

8(3/4)^2 + 14(3/4) -15 = 0 ?
8(.5625) + 10.5 -15 =0?
4.5 +10.5 -15 =0? YES!

8(-5/2)^2 + 14(-5/2) -15 = 0 ?
8(6.25) + (-35) -15 = 0 ?
50 + (-35) -15 = 0? YES!

Hope this helps.

2007-09-20 17:05:40 · answer #2 · answered by pyz01 7 · 0 0

concern one million. x^2 - 14x + 40 9 = 4 => x^2 - 14x + 40 9 - 4 = 0 => x^2 - 14x + 40 5 = 0 injury ( -14) such that it is the sum of two numbers (destructive) => x^2 - 9x - 5x + 40 5 = 0 => x (x - 9) - 5 (x - 9) = 0 (Grouping and taking away commom (x - 9)) => (x - 5) * (x - 9) = 0 as a result x = (5,9) concern 2. t^2 - 16t + sixty 4 = 25 (remedy in addition as above) => t^2 - 16t + sixty 4 - 25 = 0 => t^2 - 16t + 39 = 0 => t^2 - 13t - 3t + 39 = 0 => t*(t - 13) - 3*(t - 13) = 0 as a result t =(3,13) concern 3. I dunno what's meant through suited sq. technique, yet i think of you should proceed this variety (x - 3)^2 = sixteen Taking root on the two aspects => x - 3 = 4 or x - 3 = -4 => x = 4 + 3 or x = -4 + 3 as a result x(7, -one million)

2016-10-19 06:50:12 · answer #3 · answered by ? 4 · 0 1

8x^2 + 14x - 15 = 0

-14+- the square root of (14^2 - 4(8)(-15)) over
2(8)

-14+- the square root of (196 + 480) over
16

-14+- the square root of (676) over
16

-14+- (26) over
16

x = (3/4) and -2.5

2007-09-20 16:45:08 · answer #4 · answered by Jimmy 2 · 0 0

-5/2 & 3/4

2007-09-21 04:24:24 · answer #5 · answered by Knarf 5 · 0 0

wrong. 8x^2+14x-15=2 pts

2007-09-20 16:39:32 · answer #6 · answered by Anonymous · 1 2

firts you want to add 15 to both sides
8x^2+14x=15
then you want to get the GCF from the fist part
2x(4x+7)=15
It has been years but I think this is it.

2007-09-20 16:43:39 · answer #7 · answered by Anonymous · 0 4

(4x- 3)(2x+5)=0
4x=3 2x=-5
x=3/4 x=-5/2

2007-09-20 16:36:27 · answer #8 · answered by foofy 4 · 0 0

(4x - 3)(2x + 5) = 0
x = {-5/2, 3/4}

2007-09-20 16:36:04 · answer #9 · answered by cjcourt 4 · 1 0

x= -5/2 and x= 3/4.......there ya go!

2007-09-20 16:43:07 · answer #10 · answered by J-DUB 2 · 1 1

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