2007-09-20 15:57:55 · 8 answers · asked by LADY V, 1 in Science & Mathematics ➔ Mathematics
x^2/2-x/4=5/2
multiply by 4
2x^2 - x - 10 = 0
(2x - 5)(x + 2) = 0
x = 5/2, or x = -2
2007-09-20 16:03:11 · answer #1 · answered by vlee1225 6 · 0⤊ 0⤋
To start, I would get rid of the fractions by multiplying everything by 4.
2x^2 - x = 20
Get 0 on one side:
2x^2 - x - 10 = 0
Factor:
(2x-5) (x+2) = 0
2x - 5 = 0 or x + 2 = 0
2x = 5
x = 5/2 or x = -2
2007-09-20 23:02:49 · answer #2 · answered by lhvinny 7 · 0⤊ 0⤋
common denominator for whole problem is 4. Multiply everything by 4.
2x^2 - x = 10
now put it in quadratic equation order.
2x^2 - x - 10 = 0
and solve by factoring
2x^2 - 5x + 4x - 10 = 0
x(2x - 5)+2(2x-5) = 0
(x+2)(2x-5)=0
x = -2 or x = 5/2
2007-09-20 23:01:41 · answer #3 · answered by ccw 4 · 0⤊ 0⤋
2 x ² - x = 10
2 x ² - x - 10 = 0
(2x - 5) (x + 2) = 0
x = 5 / 2 , x = - 2
2007-09-21 03:22:09 · answer #4 · answered by Como 7 · 1⤊ 0⤋
Equation: x^2/2- x/4=5/2
Solution(s): x=2.5, x=-2
2007-09-20 23:22:41 · answer #5 · answered by Savor_Savvy 3 · 0⤊ 0⤋
I type this in:
solve(x^2/2-x/4=5/2,x);
the program (Maple) spits out:
5/2, -2
but you should probably use the quadratic equation or the method of completing the square or factoring for any of these type of problems
2007-09-20 23:02:43 · answer #6 · answered by Anonymous · 0⤊ 1⤋
x^2/2-x/4=5/2
multiply both sides by 4
2x^2-x=10
2x^2-x-10=0
(2x-5)(x+2)=0
x=5/2,-2
2007-09-20 23:02:46 · answer #7 · answered by ptolemy862000 4 · 0⤊ 0⤋
Use order of operation.
2007-09-20 23:01:54 · answer #8 · answered by Anonymous · 0⤊ 0⤋