A rocket used to lift a satellite into orbit undergoes a constant acceleration of 6.25 m/s^2. When the rocket reaches an altitude of 45 km above the surface of Earth, it is traveling at a velocity of 625 m/s. How long does it take for the rocket to reach this speed? Show your work. I really need this tonight, but I'll check this super early in the morning. If anyone knows, please help....thanks a lot!
2007-09-20 15:44:42 · 2 answers · asked by ☺♠JonasJay♫♦ 5 in Science & Mathematics ➔ Physics
Acceleration = 6.25m/s^2
Hf = 45km
Hi = 0km
Velocity = 625m/s
Time = ?
Hf = Hi + vi*t + 1/2at^2
45km(1000m/1km) = 0km + 0m/s(t) + 1/2 (6.25m/s^2)(t^2)
45000m = 3.125m/s^2(t^2)
45000m/3.125m/s^2 = t^2
14400s^2 = t^2
120 seconds = t
2007-09-20 16:04:18 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Think about it. If it starts at T=0 with velocity 0 and constant acceleration of 6.25,
it only takes 100 seconds to reach 625.
Show your work, indeed!
2007-09-20 22:55:00 · answer #2 · answered by Computer Guy 7 · 0⤊ 0⤋