math problem?

Question

Can you solve this math problem its in the system of linear Equations: Substitution: Elimination section.

In Kyotoshi, Japan, the cost of three bowls of noodles and two cartons of fresh milk is 2153 yen. Three cartons of fresh milk cost 89 yen more than one bowl of noodles. What is the cost of a bowl of noodles? A carton of fresh milk?

Answer 1

n = noodles
m = milk

"In Kyotoshi..." tells me 3n + 2m = 2153
"Three cartons..." tells me 3m - n = 89

so if you rearrange the second equation, n = 3m - 89
subsitute that in the first equation, 3(3m - 89) + 2m = 2153
distribute, 9m - 267 + 2m = 2153
simplify, 11m = 2420
therefore, m = 220

plug that 220 in an equation to solve for n, 3(220) - n = 89
660 - n = 89
n = 571

so a bowl of noodles = n = 571 yen
and a carton of fresh milk = m = 220 yen

Answer 2

N = cost of a bowl of noodles
M = cost of a carton of milk

From the first sentence, 3N + 2M = 2153
From the second sentence, 3M = N + 89

Manipulate the second equation to solve for N:

N = 3M -89

Substitue this for N in the first equation:

3(3M - 89) + 2M = 2153

9M - 267 + 2M= 2153
11M = 2420
M = 220

Using equation 2 again:

3 (220) = N + 89
660 = N + 89
N = 571

The bowl of Noodles costs 571 yen, and a carton of milk costs 220 yen.

Answer 3

Let the cost of one carton of milk be m and one bowl of noodles be n
2m +3n = 2153 .....(1)
3m - n = 89 ......(2)
(2) x 3 > 9m - 3n = 267 ......(3)
(1) + (3) > 11m = 2420
m = 220
Substitute th value of m in (1)
440 + 3n = 2153
3n = 2153 - 440 = 1713
n = 571
Therefore the cost of a bowl of noodles is 571 yen and the cost of one carton of milk is 220 yen.

Answer 4

n = cost of noodles
m = cost of milk

3n + 2m = 2153
3m = n + 89
n = 3m - 89
3(3m - 89) + 2m = 2153
9m - 267 + 2m = 2153
11m = 2420
m = 220
n = 3(220) - 89 = 660 - 89 = 571

Ans. A carton of milk costs 571 yen. A bowl of noodles costs 220 yen.

Answer 5

N=¥/bowl of noodles
M=¥/carton of milk
3N+2M=2153
3M-N=89, so N=3M-89

3N+2M=2153, so 3(3M-89)+2M=2153;
11M-267=2153
11M=2420

M=¥220

N=3M-89=3(220)-89=660-89

N=¥571

Answer 6

let the cost of noodles be x and milk be y

3x+2y=2153 (1)
3y-89=x (2)

put (2) to (1)

3(3y-89) + 2y = 2153
9y -267 + 2y =2153
11 y = 2420
y = 220

x = 3 (220) -89
= 571

Answer 7

let x be the one bowl of noodle
let y be the one carton of milk

According to question
3x + 2y = 2153 equation 1
3y= 89 + x equation 2

so, y= 89 + x / 3

now substitute this value of y in equation 1

Answer 8

3n + 2c = 2153

3c = 1n + 89

substitute n for "2c +89"

Hope that helpe

Answer 9

n=noodles
m=milk

3n+2m=2153
3m=89+n ---> n=3m-89

3(3m-89)+2m=2153
9m-267+2m=2153
11m=2460
m=220

Answer 10

much more than it is here, same with the milk