Maria and cindy both arrived early for work. Cindy arrived 23 1/2 minutes earlier than Maria. If the total number of minutes that they were early was 38, find how many minutes each girl arrived ahead of time.
2007-09-20 15:29:32 · 3 answers · asked by dzyldarchitects 2 in Science & Mathematics ➔ Mathematics
C = How early Cindy was.
M = How early Maria was.
M + 23.5 = C ( from sentence 2)
M + C = 38 (from sentence 3)
M + (M + 23.5) = 38 (substituting equation 1 into equation 2)
2 M + 23.5 = 38
2 M = 14.5
M = 7.25
7.25 + 23.5 = C
C = 30.75
Cindy was 30.75 minutes early, Maria was 7.25 minutes early.
2007-09-20 15:45:42 · answer #1 · answered by lhvinny 7 · 0⤊ 0⤋
maria arrived 14 1/2 minutes early n cindy 23 ans 1/2..i think
2007-09-20 15:44:04 · answer #2 · answered by crucita 2 · 0⤊ 0⤋
maria and cindy
lets cal them M and C
Cindy arrived 23 1/2 minutes earlier than Maria
so: C+23.5mins=M
If the total number of minutes that they were early was 38
so: C+M=38
so there are 2 ways to do this substitution and elimination
im beter with substitution so lets do that
C+23.5=M
C+M=38
since M=C+23.5 you sub that into the other equation, like:
C+ (C+23.5)=38
than its simple
2C+23.5=38
2C=38-23.5
2C=9.5
--- ----
2 2
C=4.75
now you sub back into the first equation to find M so: C+23.5=M
(4.75)+23.5=M
28.25=M
2007-09-20 15:46:34 · answer #3 · answered by bill 4 · 0⤊ 0⤋