(bi) Factorise 5x^2 + 8x + 3
I know how to do the above...Ans is (5x + 3) (x + 1)
(bii) Hence find all the factors of 583.
How to do (bii)? Show your workings clearly and explain. Thank you.
2007-09-20 14:46:26 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Lucify
Use the "tree method" .
583
|
11 - 53
Since 11 and 53 are prime numbers, that is it.
This method works best if you had a number with many factors - like 300 (see below)
300
|
30 10
6 5 2 5
2 3
Here that factors are 2, 3, 5, 2 and 5.
Hope this helps.
2007-09-20 14:58:03 · answer #1 · answered by pyz01 7 · 0⤊ 0⤋
583 is 5*10²+8*10+3.
Using the factorization from(bi), with x replaced by 10, we get
583 = (5*10+3)(10+1) = 53*11.
2007-09-20 15:14:09 · answer #2 · answered by steiner1745 7 · 0⤊ 0⤋
11 and 53
2007-09-20 14:51:21 · answer #3 · answered by sfroggy5 6 · 0⤊ 0⤋