English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

1 answers

I'm sure there is, but it's a lot more work than I want to do for 2 points. For any set of data points, an equation can be devised to fit them. The more points, the screwier the formula. Four points require no more than a cubic equation.

For the coefficients for AX^3 +Bx^2 +Cx +D, solve the following matrix division:

2 2 2 2 15
4 4 4 4 30
6 6 6 6 / 50
8 8 8 8 65

2007-09-20 14:52:31 · answer #1 · answered by Computer Guy 7 · 0 0

fedest.com, questions and answers