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ok its a trick question


if 26 clowns can blow up 26 balloons in 26 mintute, how many clowns does it take to blow up 78 balloons in 78 minutes?




ps,its not 78 clowns....

2007-09-20 14:33:06 · 6 answers · asked by psycho_girl94 2 in Science & Mathematics Mathematics

6 answers

Step 1
If 26 clowns can blow up 26 balloons in 26 minutes
1 clown can blow up 26 balloons in 26 more time than 26 clowns : 1 clown => 26 balloons => 676 min

Step 2
If 1 clown can blow up 26 balloons . So, 78 baloons take three more time at 1 clown to blow up 78 balloons => 3 x 676 = 2028 min : 1 clown => 78 balloons => 2028 min

Step 3
If 78 balloons take 2028 min to be blow up by 1 clown
to obtain 78 baloons in 78 min it will take (2026/26 = 78 min)
or 26 less time that 1 clown => these 78 balloons will be blow
up in 78 min by 26 clowns : 26 clowns => 78 ballons => 78 min.

Answer : 26 clowns


Schematicaly:

26 clowns => 26 balloons => 26 minutes

1 clown => 26 balloons => 676 minutes

1 clown => 78 balloons => 2028 minutes

26 clowns => 78 balloons => 78 minutes

2007-09-20 16:16:03 · answer #1 · answered by frank 7 · 0 0

The answer is 26 clowns. 1 clown can blow up 1 balloon in 26 minutes. Thus, he can blow up 3 balloons in 78 minutes.

If you need 78 balloons in 78 minutes, and 1 clown can blow up three balloons in 78 minutes, divide 78 by 3 to get 26.

2007-09-20 14:41:33 · answer #2 · answered by Anonymous · 0 0

26 clowns. On average, each clown blows up one balloon per 26 minutes. In 78 minutes, three times as long as the 26 minutes in which they can blow up 26 balloons, they can blow up three times as many balloons -- 78.

2007-09-20 14:40:04 · answer #3 · answered by TuretzSR 2 · 1 0

K let me see hmmm..... how is it not 78 clowns? The rate is 1 clown and blow 1 ballon up in 1 minute.

2007-09-20 14:38:13 · answer #4 · answered by Anonymous · 0 0

26

26 clowns altogether blow up one balloon per minute; they will blow up 78 balloons in 78 minutes

2007-09-20 14:38:09 · answer #5 · answered by gp4rts 7 · 0 0

I think it's 26.

2007-09-20 14:41:30 · answer #6 · answered by Lee C 3 · 1 0

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